Dear reader, due to some heavy work.we couldn’t touch with u last few months, OK.
Now we see as an with small example!
Aeration tank:
Influent BOD: 250mg/l(after 30% reduction in the Physio-chemical treatment followed by primary clarifier
Process selected: Activated sludge process
Design Condition:
F/M (Food/Microbes) =0.15
MLSS (Mixed Liquor Suspended Solids)=3000 mg/l
Calculation of Aeration Tank Volume:
F/M: So (?-MLVSS)
F/M: Food to Microbes ratio in d-1
So: influent substrate concentration in mg/l
MLVSS: Mixed Liquor Volatile Suspended solids in mg/l =0.8 x MLSS
? – Hydraulic retention time =V/Q
Where V=Aeration tank volume in cu.m
Q=Effluent flow in cu.m per day
Hence, substituting these values,
0.15=250/(v/1400 x 0.8 x 3000)
V=972 KL, selected volume =1400 KL
I have just read your topic on aeration volume calculation today. It’s simple and very interesting to me but I would like to know where did you get the number 1400 in your formula or equation? 0.15= 250/(v/1400×0.8×3000). Thank you.
Exactly, The information is valuable, Until, eventually the number 1400 was found unknown.
Acc. to the formula I use to calc. the Volume is
V= Q.BOD / (F/M).MLSS
And my question is that how will be the volume of the MBBR based aeration can be calculated?
Dear Sir
Every think OK.but I don’t know about the value of 1400. For which using that one
1400 is assumption fig of water effluent quantity in M3/day
hai sir
i need differnt example on areartion tank design, can you give me .
Where did you get value 1400 in your formula and v express to what?
resolved check the post
1400 is plant capacity I.e. You want to handle 1400 m3 per day. This can be as per your need.
e.g. I am going to establish Etp plant of 900 m3 per day then Q= 900 m3/ day Accordingly Vaerationn will be less.
Design an aeration tank for a flow of 790 m3/ hour with BOD of 200 mg/L an F/M ratio o f0.4 day-1 and SVI of 100 ml/gram. Air supply rate is 10 m3/ m2 of sewage /day. Assume W: L = 1:4.
PLEASE IF ANY ONE CAN SOLVE THIS
Explain the equation sir.
i cant understand the KL the volume tank =972 KL ITS MEAN 972,000LITERS?
KL mean Kilo Litre (1000 Litre)
how we calculate the volume didnt arrive to find v
Dear sir,
Thanks for the example..it was realy very helpful
But i Didnt understood the last equation..from where did u get v=972?
Pls someone explain..
V mean Volume of Aeration Tank in m3 (in capacity of m3 holding) and 1400 mean treatment qty to be treated /day
Sir, my capacity tank has a capacity of 480 kld/per day so how much capacity will be the air blower?The tank has to be lane in the air grid.
What is the basics of considering F/M ratio – 0.15, MLSS – 3000 mg/lit? How it was link with COD And BOD? Or Its Just assumptions.
Please explain..!!
0.15=250/(v/1400 x 0.8 x 3000)
V=972 KL, selected volume =1400 KL
Please check calculation.
After solving the equation We get V= 972KL, but selectedvolume is = 1400Kl
But Why please explain
Dear sir,
We need to design aeration plz help,
Flow rate = 167cum/hr
Inlet BOD= 105 ppm
MLSS = 9000ppm
Please help for above
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