Did you Select, correct Capacity Air blower for your aeration Tank/Basin ? Any water and wastewater treatment process Air Requirement is inevitable for clear process. many engineer is is still confusing and trouble to choose exact capacity for that application,
for your easy understand we given simple solution with example.
HP of the Blower / Fan = ( CFM X [....]
Read moreDetermination of volatile matter reduction in sludge is complicated because of the changes occurring during sludge digestion.
The calculation used to determine percent volatile matter (VM) reduction is
[%VMin – %VMout] X100
% of Volatile Matter Reduction (VM) = ——————————-
[%VMin – (%VMin X % VMout)]
Using the digester data provided below, Determine [....]
Read moreMeasurement of Sediment oxygen demand (SOD) is a measure of the oxygen demand characteristics of the bottom sediment which affects the dissolved oxygen resources of the overlying water. To measure SOD, a bottom sample is especially designed to entrap and seal a known quantity of water at the river bottom. Changes in DO concentrations (approximately 2 h, or until the [....]
Read moreDetermination of Phosphate
The neutralized sample is reacted with ammonium molybdate and stannous chloride.the blue color obtained is matched against that produced with a series of standard phosphate solution, visually or with spectrophotometer at 690mu.
Reagents:
1.Phenolphthalein indicator solution
2.Approximately 4N sulfuric acid
3.Ammonium Molybdate Solution
4.Standard Phosphate solution
Procedure:
To a 50 ml.sample containing not more than 0.15mg.of phosphate(as [....]
Read moreThis example in connection with our previous post,
How to calculate Aeration Tank Volume?
Total BOD to be removed (Influent) = 250 mg/l (assume) x 1400 = 350 kg/Day (we consider 1400 M3/Day Effluent Plant)
Hence O2 to be transferred =350 kg/Day
Method of Aeration = Fine Bubble Diffuser
[....] Read moreSOTE (Standard O2 Transfer Efficiency For 300
Dear reader, due to some heavy work.we couldn’t touch with u last few months, OK.
Now we see as an with small example!
Aeration tank:
Influent BOD: 250mg/l(after 30% reduction in the Physio-chemical treatment followed by primary clarifier
Process selected: Activated sludge process
Design Condition:
F/M (Food/Microbes) =0.15
MLSS (Mixed Liquor Suspended Solids)=3000 mg/l
Calculation of Aeration Tank Volume: [....]
Read more